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my solution

the vertical component of the 500N force = 500*sin30 = 250 N down

the north component of the 500 N force = 500*cos30 north

the sum of the north-south components = 300 north + 500*cos30 north + 400 south

Net north-south component = 300 + 500*cos30 - 400 = 333 N

The 333 N force vector and the 250 N force vector are perpendicular to each other. The vector that represents the sum of these 2 vectors is the hypotenuse of the right triangle formed by the 3 vectors.

Magnitude of total force = (250^2 + 333^2)^0.5 = 416 N